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UB 457x191x67 (Ub6)

The document provides design calculations for the connection detail of a limestone crusher house in a thermal power project. It details the specifications and calculations for the number of bolts required for a beam cleat, including shear and bearing capacities. The final recommendation is to provide four 24 mm diameter bolts based on the calculations performed.

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Farhan Danish
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14 views3 pages

UB 457x191x67 (Ub6)

The document provides design calculations for the connection detail of a limestone crusher house in a thermal power project. It details the specifications and calculations for the number of bolts required for a beam cleat, including shear and bearing capacities. The final recommendation is to provide four 24 mm diameter bolts based on the calculations performed.

Uploaded by

Farhan Danish
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as XLSX, PDF, TXT or read online on Scribd
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STRUC-MECH ENGINEERS,RANCHI,JHARKHAND

PROJECT NAME FGD PACKAGE(3 X 660MW BARH STAGE-1) NTPC DWG NO.-9558-OO1-109-PVC-C-022

UNIT LIMESTONE CRUSHER HOUSE-1 BHEL DWG NO.-IS-1-GA-723-406-C022

CONTRACTOR NAME BHARAT HEAVY ELECTRICALS LIMITED DESIGNED BY VIKASH THAKUR


SUBJECT DESIGN CALCULATION FOR CONNECTION DETAIL

Calculation of No. Of bolts for BEAM CLEAT

FOR UB 457x191x67

UB 457X191X67 Depth of member 453 mm


flange thickness 12.7 mm
Web Plate width 428 mm
Web plate thickness 8.5 mm
Cleat angle 110X110X10
Angle Thickness 10.0 mm
Web area 3634.60 mm^2
Web shear 3634.60 T
Shear Force/ Cleat 1817.30 T
shear area of cleat 1817.30 mm^2
Length of cleat 300 mm
min. size required Cleat thickness= Shear area of cleat/length of cleat 6.06 mm^2 SAFE

As per General Notes, Provide HSFG Bolts of Grade 8.8S


For 8.8S grade bolts, Fub= 800 Mpa
Assume grade of steel Fu= 410 Mpa
Assume dia of Bolt d= 24 mm
From Table 19, IS 800:2007, Dia of Hole d0= 26 mm
Axial Capacity of steel= 1.00 (T/cm^2)
from Table 5.1, IS 808:1989 Sectional area for member= 36.35 cm^2
As per General Notes, force on member= 60% of section strength
0.6 x Area x axial capacity of steel = 218.08 KN
From Cl. 10.2.4.2, Pg. No.-74, IS 800:2007
End distance = 1.5 x d0
1.5 x 22 = 39 mm
Lets , Provide 45 mm

From Table 19, Pg. No.- 73, is 800:2007 Pitch Distance= 2.5 x d
2.5 x 20 = 60 mm
Lets , Provide 70 mm

From ,Cl. 10.3.3, pg no.-75,IS 800:2007 Shear Capacity of Bolt


Vdsb = Vnsb/Ymb
Strength of the bolt in single shear,
Vdsb = Anb x (Fub/(1.732*Ymb))
From IS : 1367, Part-1 Anb= 0.78 x shank area of bolt
Anb= 0.78 x (3.414 x d x d)/4 352.85 mm^2
From Table 5, Pg-30, IS 800:2007, Ymb = 1.25
so, Strength of the bolt in Single shear
245.03*(800/(1.732*1.25))= 90.54 KN

From Cl. 10.3.4, pg no.-75,IS 800:2007 Bear Capacity of Bolt


Vdpb = Vnpb/Ymb
Vdpb = (2.5 x Kb x d x t x Fu /Ymb)
Where , Kb Smaller of ( e/3d0 , p/3d0-0.25, Fub/Fu , 1.0)
By putting values we have
Kb Smaller of ( 0.61,0.81,1.95 1.0)
0.61
Now, Vdpb = (2.5 x 0.61 x 20 x 10 x 410 /1.25) 100.04 KN

Hence , Strength of Bolt = Min ( Shear Strength , Bear Strength)


So 90.54 KN

Number of Bolt Required=


(Force on member/ Strength of bolt)=
(218.08/90.54)= 2.41 No. 3.00 No.

PROVIDE 4 NO.,24 DIA. BOLT

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