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Quadratics

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solve the following pairs of simultaneous expressions

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Author: Joe Berwick This type of activity is known as Practice. Please read the guidance notes here, where you will find useful information for running these types of activities with your students.…
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Wyznacz wszystkie możliwe rozwiązania układu równań w zbiorze liczb rzeczywistych i sprawdź układ. Rozwiązanie: - wprowadzamy pomocniczą u i v odpowiednio za wartości ∛(x+y)=u i √(x-y)=v, otrzymamy postać zredukowaną układu równań z założeniem, że x-y≥0 - z otrzymanego układu równań obliczmy wartości u=2 i v=2, - otrzymane wartości podstawiamy do naszego pomocniczego układu równań {∛(x+y)=u {√(x-y)=v i wyznaczamy dla jakich wartości (x, y) układ równań posiada rozwiązanie - jedynym...
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Usuwanie niewymierności z mianownika ułamka polega na przeniesieniu symbolu pierwiastka z mianownika do licznika ułamka. W tym celu należy pomnożyć licznik i mianownik danego ułamka przez taką wartość, żeby w mianowniku otrzymać liczbę rzeczywistą różną od zera. Usuwanie niewymierności z mianownika ułamka polega najczęściej na pomnożeniu licznika i mianownika przez taką wartość, żeby zastosować wzory skróconego możenia tj. (a – b)(a + b) = a² - b² (a - b)(a² + ab + b²) = a³ - b³ (a + b)(a²...
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Componendo dividendo in algebra | SureSolv